100% PASS-RATE ACTUAL 1Z0-830 TEST ANSWERS | ACCURATE 1Z0-830 RELIABLE EXAM REVIEW: JAVA SE 21 DEVELOPER PROFESSIONAL

100% Pass-Rate Actual 1z0-830 Test Answers | Accurate 1z0-830 Reliable Exam Review: Java SE 21 Developer Professional

100% Pass-Rate Actual 1z0-830 Test Answers | Accurate 1z0-830 Reliable Exam Review: Java SE 21 Developer Professional

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Oracle Java SE 21 Developer Professional Sample Questions (Q22-Q27):

NEW QUESTION # 22
Given:
java
record WithInstanceField(String foo, int bar) {
double fuz;
}
record WithStaticField(String foo, int bar) {
static double wiz;
}
record ExtendingClass(String foo) extends Exception {}
record ImplementingInterface(String foo) implements Cloneable {}
Which records compile? (Select 2)

  • A. WithStaticField
  • B. ExtendingClass
  • C. WithInstanceField
  • D. ImplementingInterface

Answer: A,D

Explanation:
In Java, records are a special kind of class designed to act as transparent carriers for immutabledata. They automatically provide implementations for equals(), hashCode(), and toString(), and their fields are final and private by default.
* Option A: ExtendingClass
* Analysis: Records in Java implicitly extend java.lang.Record and cannot extend any other class because Java does not support multiple inheritance. Attempting to extend another class, such as Exception, will result in a compilation error.
* Conclusion: Does not compile.
* Option B: WithInstanceField
* Analysis: Records do not allow the declaration of instance fields outside of their components.
The declaration of double fuz; is not permitted and will cause a compilation error.
* Conclusion: Does not compile.
* Option C: ImplementingInterface
* Analysis: Records can implement interfaces. In this case, ImplementingInterface implements Cloneable, which is valid.
* Conclusion: Compiles successfully.


NEW QUESTION # 23
Given:
java
public class Test {
public static void main(String[] args) throws IOException {
Path p1 = Path.of("f1.txt");
Path p2 = Path.of("f2.txt");
Files.move(p1, p2);
Files.delete(p1);
}
}
In which case does the given program throw an exception?

  • A. Both files f1.txt and f2.txt exist
  • B. Neither files f1.txt nor f2.txt exist
  • C. File f2.txt exists while file f1.txt doesn't
  • D. File f1.txt exists while file f2.txt doesn't
  • E. An exception is always thrown

Answer: E

Explanation:
In this program, the following operations are performed:
* Paths Initialization:
* Path p1 is set to "f1.txt".
* Path p2 is set to "f2.txt".
* File Move Operation:
* Files.move(p1, p2); attempts to move (or rename) f1.txt to f2.txt.
* File Delete Operation:
* Files.delete(p1); attempts to delete f1.txt.
Analysis:
* If f1.txt Does Not Exist:
* The Files.move(p1, p2); operation will throw a NoSuchFileException because the source file f1.
txt is missing.
* If f1.txt Exists and f2.txt Does Not Exist:
* The Files.move(p1, p2); operation will successfully rename f1.txt to f2.txt.
* Subsequently, the Files.delete(p1); operation will throw a NoSuchFileException because p1 (now f1.txt) no longer exists after the move.
* If Both f1.txt and f2.txt Exist:
* The Files.move(p1, p2); operation will throw a FileAlreadyExistsException because the target file f2.txt already exists.
* If f2.txt Exists While f1.txt Does Not:
* Similar to the first scenario, the Files.move(p1, p2); operation will throw a NoSuchFileException due to the absence of f1.txt.
In all possible scenarios, an exception is thrown during the execution of the program.


NEW QUESTION # 24
Given:
java
final Stream<String> strings =
Files.readAllLines(Paths.get("orders.csv"));
strings.skip(1)
.limit(2)
.forEach(System.out::println);
And that the orders.csv file contains:
mathematica
OrderID,Customer,Product,Quantity,Price
1,Kylian Mbappe,Keyboard,2,25.50
2,Teddy Riner,Mouse,1,15.99
3,Sebastien Loeb,Monitor,1,199.99
4,Antoine Griezmann,Headset,3,45.00
What is printed?

  • A. An exception is thrown at runtime.
  • B. Compilation fails.
  • C. arduino
    2,Teddy Riner,Mouse,1,15.99
    3,Sebastien Loeb,Monitor,1,199.99
  • D. arduino
    1,Kylian Mbappe,Keyboard,2,25.50
    2,Teddy Riner,Mouse,1,15.99
  • E. arduino
    1,Kylian Mbappe,Keyboard,2,25.50
    2,Teddy Riner,Mouse,1,15.99
    3,Sebastien Loeb,Monitor,1,199.99
    4,Antoine Griezmann,Headset,3,45.00

Answer: A,B

Explanation:
1. Why Does Compilation Fail?
* The error is in this line:
java
final Stream<String> strings = Files.readAllLines(Paths.get("orders.csv"));
* Files.readAllLines(Paths.get("orders.csv")) returns a List<String>,not a Stream<String>.
* A List<String> cannot be assigned to a Stream<String>.
2. Correcting the Code
* The correct way to create a stream from the file:
java
Stream<String> strings = Files.lines(Paths.get("orders.csv"));
* This correctly creates a Stream<String> from the file.
3. Expected Output After Fixing
java
Files.lines(Paths.get("orders.csv"))
skip(1) // Skips the header row
limit(2) // Limits to first two data rows
forEach(System.out::println);
* Output:
arduino
1,Kylian Mbappe,Keyboard,2,25.50
2,Teddy Riner,Mouse,1,15.99
Thus, the correct answer is:Compilation fails.
References:
* Java SE 21 - Files.readAllLines
* Java SE 21 - Files.lines


NEW QUESTION # 25
Given:
java
Optional o1 = Optional.empty();
Optional o2 = Optional.of(1);
Optional o3 = Stream.of(o1, o2)
.filter(Optional::isPresent)
.findAny()
.flatMap(o -> o);
System.out.println(o3.orElse(2));
What is the given code fragment's output?

  • A. Optional.empty
  • B. Compilation fails
  • C. 0
  • D. Optional[1]
  • E. 1
  • F. 2
  • G. An exception is thrown

Answer: E

Explanation:
In this code, two Optional objects are created:
* o1 is an empty Optional.
* o2 is an Optional containing the integer 1.
A stream is created from o1 and o2. The filter method retains only the Optional instances that are present (i.e., non-empty). This results in a stream containing only o2.
The findAny method returns an Optional describing some element of the stream, or an empty Optional if the stream is empty. Since the stream contains o2, findAny returns Optional[Optional[1]].
The flatMap method is then used to flatten this nested Optional. It applies the provided mapping function (o -
> o) to the value, resulting in Optional[1].
Finally, o3.orElse(2) returns the value contained in o3 if it is present; otherwise, it returns 2. Since o3 contains
1, the output is 1.


NEW QUESTION # 26
Which of the following statements are correct?

  • A. You can use 'protected' access modifier with all kinds of classes
  • B. You can use 'private' access modifier with all kinds of classes
  • C. You can use 'final' modifier with all kinds of classes
  • D. You can use 'public' access modifier with all kinds of classes
  • E. None

Answer: E

Explanation:
1. private Access Modifier
* The private access modifiercan only be used for inner classes(nested classes).
* Top-level classes cannot be private.
* Example ofinvaliduse:
java
private class MyClass {} // Compilation error
* Example ofvaliduse (for inner class):
java
class Outer {
private class Inner {}
}
2. protected Access Modifier
* Top-level classes cannot be protected.
* protectedonly applies to members (fields, methods, and constructors).
* Example ofinvaliduse:
java
protected class MyClass {} // Compilation error
* Example ofvaliduse (for methods/fields):
java
class Parent {
protected void display() {}
}
3. public Access Modifier
* Atop-level class can be public, butonly one public class per file is allowed.
* Example ofvaliduse:
java
public class MyClass {}
* Example ofinvaliduse:
java
public class A {}
public class B {} // Compilation error: Only one public class per file
4. final Modifier
* finalcan be used with classes, but not all kinds of classes.
* Interfaces cannot be final, because they are meant to be implemented.
* Example ofinvaliduse:
java
final interface MyInterface {} // Compilation error
Thus,none of the statements are fully correct, making the correct answer:None References:
* Java SE 21 - Access Modifiers
* Java SE 21 - Class Modifiers


NEW QUESTION # 27
......

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